IBM InfoSphere DataStage v8.5 - C2090-421

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IBM C2090-421 Exam Syllabus Topics:

IBM InfoSphere DataStage v8.5 Sample Questions:

Question 1

You are working on a project that contains a large number of jobs contained in many folders. You would like to review the jobs created by the former developer of the project. How can you find these jobs?

A. Use the Advanced Find feature contained in the Designer interface.
B. While selecting the top folder in the project, choose Find Dependencies.
C. Filter jobs in Director Client's Repository window.
D. Sort the jobs by date in the Repository window.

Question 2

A job contains a Sort stage that sorts a large volume of data across a cluster of servers. Due to new requirements, the customer has requested that this sorting be done on a subset of servers identified in the configuration file to minimize impact on database nodes. The $APT_CONFIG_FILE shows no sort disk pool for any node. Which two steps will accomplish this? (Choose two.)

A. Create a sort scratch disk pool with a subset of nodes in the parallel configuration file.
B. Define a non-default node pool with a subset of nodes in the parallel configuration file.
C. Use the environment variable $APT_SCRATCH_SPACE_SORT_USAGE.
D. Have an appropriate node constraint within the Sort stage.
E. Assign a separate config file just for the Sort stage.

Question 3

Which two statements are true about DataStage Parallel Build stages? (Choose two.)

A. On the Logic Post-Loop, you specify code that runs after all input records have been processed.
B. The Build stage generates a C/C++ source file that is compiled and linked outside of DataStage.
C. Build stages can only be used in a job that has Runtime Column Propagation (RCP) enabled.
D. The Build stage can be programmed to read and write automatically or code can be written to manually read and write rows.

Question 4

What are three valid join operations for the Join stage? (Choose three.)

A. Right outer join
B. Inner Join
C. Bottom inner join
D. Top outer join
E. Left outer join

Question 5

Your job uses the MQ connector stage to read messages from an MQ queue. The job should retrieve the message ID into the MessageID field and parse the payload into two fields: Name is to get the first ten characters, Description is to get the remaining characters.
What will accomplish this?

A. First column is MessageID as Binary 24; second column is Name as Binary 10; select WSMG. MSPAYLOAD data element; third column is Description as VarBinary 200; select WSMG.MSPAYLOAD data element.
B. First column is MessageID; select the WSMQ.MSGID data element for the Message ID field; second column is Name; select WSMG.MSPAYLOAD data element; third column is Description; select WSMG.MSPAYLOAD data element.
C. First column is MessageID; select the WSMQ.MSGID data element for the Message ID field; second column is Name as Binary 10; third column is Description as VarBinary 200.
D. First column is MessageID; select the WSMQ.MSGID data element for the Message ID field; column is Description as VarBinary 200; third column is Name as Binary 10.

Solutions: